Question

the sum of two integers is -11 and their products is _80 what are the two integers​

Answer 1

The sum of two numbers is 8, and their product is 80. Let x represent one of the numbers, and write an expression for the other number in terms of x. Use the expressions to write an equation that models the situation given above. Use the Quadratic Formula to solve the equation. Write the solutions in terms of i

Answer 2

Answer:

Question:-

The sum of two numbers is -11. The product of these numbers is -80, find the numbers.

Solution:-

Let the numbers be x and y

x + y = -11

x = -11 - y — (i)

xy = -80

x = -80/y — (ii)

Now we compare both the equations:-

Since we know that both the equations stand for the value of x, we can say that they are equal to each other.

-11 - y = -80/y

(-11 -y)y = -80

-11y - y² = -80

-y² - 11y = -80

Now we factorise this term:-

-y² - 11y + 80 = 0

-y² - 16y + 5y + 80 = 0

y[-y - 16] - 5[-y - 16] = 0

[y - 5][-y - 16] = 0

y = -16 OR 5

Let’s take the value of y as 5

Now we find the value of x:-

x + y = -11

x + 5 = -11

x = -11 -5

x = -16

The integers are:-

-16 and 5

Hope it helps

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