Question

the sum of two integers is 41.when 3 times the smaller is subtracted from the larger the result is 17. find the two integers​

Answer 1

GiveN :

• Sum of two integers = 41
• When 3 times the smaller is subtracted from the larger the result is 17.

To FinD :

• The two integers .

SolutionN:-

Let the smaller integer be x and the larger integer be y.

• Sum of two integers= 41

$: \implies \tt{ x + y = 41 \: \: ..... (1)}$

• When 3 times the smaller is subtracted from the larger the result is 17.

$: \implies \sf{y - 3x = 17}$

$: \implies \tt{y = 17 + 3x \: \: .....(2)}$

Substituting the value of equation (2) in equation (1) .

$: \implies \sf{x + y = 41}$

$: \implies \sf{x + 17 + 3x =4 1}$

$: \implies \sf{4x+ 17 =4 1}$

$: \implies \sf{4x = 4 1 - 17}$

$: \implies \sf{4x =2 4}$

$: \implies \sf{x = \dfrac{2 4}{4}}$

$: \implies \underline{\tt{x =6}}$

Putting the value of x in equation (1) :

$: \implies \sf{6+ y = 41}$

$: \implies \sf{ y = 41-6}$

$: \implies \underline{\tt{ y = 35}}$

$\huge{\therefore}$ The two integers are 6 and 35.

Answer 2

GiveN :

• Sum of two integers = 41
• When 3 times the smaller is subtracted from the larger the result is 17.

To FinD :

• The two integers .

SolutionN:-

Let the smaller integer be x and the larger integer be y.

• Sum of two integers= 41

$: \implies \tt{ x + y = 41 \: \: ..... (1)}$

• When 3 times the smaller is subtracted from the larger the result is 17.

$: \implies \sf{y - 3x = 17}$

$: \implies \tt{y = 17 + 3x \: \: .....(2)}$

Substituting the value of equation (2) in equation (1) .

$: \implies \sf{x + y = 41}$

$: \implies \sf{x + 17 + 3x =4 1}$

$: \implies \sf{4x+ 17 + =4 1}$

$: \implies \sf{4x = 4 1 - 17}$

$: \implies \sf{4x =2 4}$

$: \implies \sf{x = \dfrac{2 4}{4}}$

$: \implies \underline{\pink{\bf{x =6}}}$

Putting the value of x in equation (1) :

$: \implies \sf{6+ y = 41}$

$: \implies \sf{ y = 41-6}$

$: \implies \underline{\pink{\bf{ y = 35}}}$

$\huge{\therefore}$ The two integers are 6 and 35.