Question

The sum of two integers is 41. When 3 times the smaller(x) is subtracted from the larger(y) the results is17

Answer 1

Step-by-step explanation:

given that

sum of two integers =41

let larger be y

smaller be x

x+y=41 (eq 1)

y-3x=17

y=17+3x

substitute in eq 1

x+17+3x=41

4x=41-17

4x=24

x=24/4

x=6

x+y=41

y=41-6

y=35

therefore x=6 and y=35