Question

The sum of two integers is 65. If one of them is -31, find the other.
The difference of an integer a and (-6) is 4. Find the value of a.
Write a pair of integers whose sum gives​

Answer 1

Correct question :

1) The sum of two integers is 65. If one of them is -31, find the other.

2) The difference of an integer a and (-6) is 4. Find the value of a.

Solution :

1) Given,

sum of two integers is 65

one number = -31

other number = x

∴ -31 + x = 65

x = 65 + 31

x = 96

∴ other number is 96

2) given ,

difference between a and -6 is 4

a - (-6) = 4

a + 6 = 4

a = 4 - 6

a = -2

∴ value of a is -2

Answer 2

$\huge\bold \color{brown} \mathtt{\boxed{\boxed{Question}}}$

The sum of two integers is 65. If one of them is -31, find the other.

$\bold \color{red} \mathtt</strong><strong>{</strong><strong>\</strong><strong>boxed</strong><strong>{⭐Answer⭐}</strong><strong>}</strong><strong>$

Given :-

• sum of two integers = 65
• One of then is - 31

To find

• Other number

Let x and y be the number.

• ∴ x = - 31 , y = ?
• So, according to the question,

$\implies \: x + y = 65$

$\implies( - 31) + y = 65$

$\implies \: y = 65 + 31$

$\color{green}{ \boxed{ \implies \: y = 96}}$

So another number is 96.

_____________________________

$\huge\bold \color{brown} \mathtt{\boxed{Question}}$

The difference of an integer a and (-6) is 4. Find the value of a.

$\bold \color{red} \mathtt</strong><strong>{</strong><strong>\</strong><strong>boxed</strong><strong>{⭐Answer⭐}</strong><strong>}</strong><strong>$

By assuming Closure property of Subtraction [a-b=c],

Let, a = a, b=-6, c=4

$\implies a – (-6) = 4$

$\implies a + 6 = 4$

$\implies a = 4-6$

$\color{green}{ \boxed{ \implies \: a = -2}}$

Value of a is -2.