Question

The sum of two middle terms of the ap: -4/3,-1,-2/3,....,13/3

Answer 1

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Answer 2

The Ap is..

-4/3,-1,-2/3...13/3

Common difference d = a2 -a1 = -1 - (-4/3)

d = -1+ 4/3=1/3

Number of terms in the AP =n

We know that last term of AP

an= a1 + (n-1)d

an=13/3 a1=-4/3

so.....

13/3 = -4/3 + (n-1)(1/3)

13/3 + 4/3 = (n-1)/3

17/3=(n-1)/3

17=n-1

n=18

as n is equal to 18..... so it will have two middle points ie. 18/2 & 18/2 +1

=9 & 10

so we have to find sum of 9th and 10th term of AP`

a9 +a10 = [a1 +(9-1)(1/3)] + [a1+ (10-1)(1/3)]

a9 + a10 =-4/3 +8/3 + (-4/3) +9/3

a9 + a10 =9/3

So the sum of middle terms of AP is 9/3