Math, asked by nassrahd02, 1 year ago

The sum of two middle terms of the ap: -4/3,-1,-2/3,....,13/3

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Answered by ydharmendra888
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Answered by Anonymous
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The Ap is..


-4/3,-1,-2/3...13/3


Common difference d = a2 -a1 = -1 - (-4/3)


d = -1+ 4/3=1/3


Number of terms in the AP =n


We know that last term of AP


an= a1 + (n-1)d


an=13/3 a1=-4/3


so.....


13/3 = -4/3 + (n-1)(1/3)


13/3 + 4/3 = (n-1)/3


17/3=(n-1)/3


17=n-1


n=18


as n is equal to 18..... so it will have two middle points ie. 18/2 & 18/2 +1


=9 & 10


so we have to find sum of 9th and 10th term of AP`


a9 +a10 = [a1 +(9-1)(1/3)] + [a1+ (10-1)(1/3)]


a9 + a10 =-4/3 +8/3 + (-4/3) +9/3


a9 + a10 =9/3


So the sum of middle terms of AP is 9/3



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