The sum of two natural number is 15and their recipracals is3/10. find the numbers
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given a+b=15 ---I
and (1/a)+(1/b)=3/10 ----II
solving II we get ab=50 ---III
from I, a=15-b
substitue value of this a in III
we get b^2 -15b+50=0
solve for b
b can either be 10 or 5
putting this in I , we get a can be 10 or 5
answer is 10 and 5
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