Question

the sum of two natural number is 25 and the difference of their squares is 7 then what is the difference of 2 numbers

Answer 1

Answer:

$\frac{7}{25}$

Step-by-step explanation:

Let the two numbers be x and y.

ATQ,

x + y = 25-------------------- 1

${x}^{2} - {y}^{2} = 7$

$= (x + y)(x - y) = 7$

= 25 × (x - y) = 7 [ from equation 1]

$= x - y = \frac{7}{25}$

THEREFORE, THE DIFFERENCE BETWEEN THE TWO NUMBERS IS 7/25.

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Answer 2

$\huge\boxed{\mathtt\red{Solution :-}}$

Given :-

• sum of two numbers is 25.
• Difference of their square is 7.

To Find :-

• Difference of the two numbers.

Assumption :-

• Let the two numbers be a and b

Solving :-

According to the question :-

✒ a+b = 25

Now,

✒ a²-b² = 7

✒ (a+b)(a-b) = 7

✒ 25(a-b) = 7

$\large\boxed{\mathtt\green{∴(a-b) = \frac{7}{25}}}$

Answer :-

$\large\boxed{\mathtt\blue{Therefore,\: the \:difference}}\\{\large{\boxed{\mathtt\blue{ between\: the \:two \:numbers \:is \:\frac{7}{25}}}}}$