Question

The sum of two natural numbers is 1095 and their HCF is 73 . How many pairs of such numbers are possible.

Answer is 4, Why?

Answer 1

Answer:

hope it will help you...

Step-by-step explanation:

because

let 73x and 73y

73x + 73y = 1095

73(x+y) = 1095

x+y= 1095/ 73

x+y = 15

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Answer 2

The answer is 4, because

Step-by-step explanation:

• It has been given that the sum of two natural numbers is 1095 and their HCF is 73. So, let the two numbers be x and y.

Now,

$73x+73y=1095$

⇒ $73(x+y)=1095$

⇒ $x+y=15$'

So,

For $x=1$, $y=14$, the numbers are $1\cdot73+14\cdot73=73+1022=1095$

For, $x=7$, $y=8$, the numbers are $7\cdot73+8\cdot73=511+584=1095$

For, $x=2$, $y=13$, the numbers are $2\cdot73+13\cdot73=146+949=1095$

For,$x=4$, $y=11$, the numbers are $4\cdot73+11\cdot73=292+803=1095$

Therefore, the number of such pairs is $4$.