The sum of two natural numbers is 20 while their difference is 4 Find the numbers
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12,8
Step-by-step explanation:
let the two no. be x & y
x+y = 20. (1)
x-y = 4. (2)
x= 20-y. from eq.(1)
putting the value of x in eq. (2)
20 - y - y = 4
20 - 2y = 4
-2y = 4-20
-2y = -16
y = 16/2
y = 8
x = 20 - y
x = 20 - 8
x = 12.
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