The sum of two natural numbers is 20 while their difference is 4. Find the numbers
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Answered by
2
let the numbers be x and y
x+y=20 *
x-y=4
20-y-y=4
20-2y=4
-2y=-16
y=8
x=20-8=12
Answered by
1
let the first number is x and second is y (x>y)
ATQ
x-y=4
x+y=20
by adding
2x=24
x=12
we know that x+y=20
12+y=20
y=20-12
y=8
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