Question

The sum of two natural numbers is 9 and the sum of their reciprocals is 9\20.Find the numbers.​

Answer 1

Answer:

By first condition ,

be X is 1st number and Y be 2nd number.

X + Y = 9

By second condition ,

No real value of x is possible. so question is incorrect

Step-by-step explanation:

Given,

Sum of two numbers = 9

Sum of their reciprocal = 9 / 20

To find: The numbers

Solution:

Let the one number be x.

Then another number = ( 9 - x)

Then the equation formed will be,

\begin{gathered}\dfrac{1}{x} + \dfrac{1}{(9-x)} = \dfrac{9}{20}\\\\\dfrac{(9-x)+x}{x(9-x)} = \dfrac{9}{12}\\\\12 \times 9 = 9 (9x -x^2)\\\\108 = 18x - 9x^2\\\\12 = 2x - x^2\\\\x^2 - 2x + 12 = 0\\\\\end{gathered}x1+(9−x)1=209x(9−x)(9−x)+x=12912×9=9(9x−x2)108=18x−9x212=2x−x2x2−2x+12=0

No real value of x is possible.

Answer 2

Step-by-step explanation:

athe

pakshe very difficult aana