the sum of two no is 11 and their reciprocal is 11/28 find the numbers
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let the 1st number be x
and the 2nd number be 11 - x
According to question
1/x + 1/11-x = 11/28
11 - x + x/(x)(11 - x) = 11/28
11/11x - x^2 = 12/28
308 = 132x -12x^2
12x^2 - 132x +308 = 0
now factorise it u will get your answer
and the 2nd number be 11 - x
According to question
1/x + 1/11-x = 11/28
11 - x + x/(x)(11 - x) = 11/28
11/11x - x^2 = 12/28
308 = 132x -12x^2
12x^2 - 132x +308 = 0
now factorise it u will get your answer
priyanshu8595:
thank you
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