The sum of two no is 18 and the sum of thier reciprocals is 1/4 find the no
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Answered by
0
Answer:
two no is 18..
one no is 1/4
other no be x
1/4+x=18
×=18-1/4
=72/4-1/4
=71/4 @nswer
hope it's helps u
Answered by
1
Answer:
6 and 12
Step-by-step explanation:
Let the numbers are x and y
so sum x+y=18------------(1)
sum of reciprocals 1/x+1/y=1/4
(x+y)/xy=1/4
18/xy=1/4
xy=72
now x+y=18
x+xy/x=18
x+72/x=18
x2+72=18x
x2-18x+72=0
x2-12x-6x+72=0
x(x-12)-6(x-12)=0
(x-6)(x-12)=0
x=6,12
if x=6 then y=18-6=12
so the numbers are
6 and 12
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