the sum of two no is 18 the sum of their reciprocal
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here is your answer.....
sorry the pic is wrong clicked....
the right solution is....
18-x/(18x - x^2) + x/(18x - x^2)
= 18/(18x - x^2)
1/(1x - x^2)
= 1/x(1-x)
sorry the pic is wrong clicked....
the right solution is....
18-x/(18x - x^2) + x/(18x - x^2)
= 18/(18x - x^2)
1/(1x - x^2)
= 1/x(1-x)
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Answered by
2
Answer:
refer to the attachment for the solution..
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