the sum of two no. is 56.one no. is 8 more than twice the other no. find the equation
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Let the smaller number be x other be y
so by the second condition given in your question we get equation
y = 2x + 8
By the condition given in your question we get equation
x + 2x + 8 = 56
3x + 8 = 56
3x = 48
x = 16
y = 2x + 8
= 32 + 8
= 40
so two numbers are 16 & 40
so by the second condition given in your question we get equation
y = 2x + 8
By the condition given in your question we get equation
x + 2x + 8 = 56
3x + 8 = 56
3x = 48
x = 16
y = 2x + 8
= 32 + 8
= 40
so two numbers are 16 & 40
sanika16:
u r great
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