The sum of two no. is 710.If bigger no. is divided smaller one then the quotient is 12 and remainder is 8 .Find the no.
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Solution. Let the larger number be x and smaller number be y.
As per the first given condition,
x + y = 97 ........eq. no. (1)
As per the second condition,
Dividend = Divisor × Quotient + Remainder
x = y × 7 + 1
∴ x = 7y + 1
∴ x – 7y = 1 .......(2)
Subtracting (2) from (1),
x + y = 97
x – 7y = 1
(-) (+) (-)
8y = 98
∴ y = 96/8
∴ y = 12
Substituting y = 12 in equation (1)
∴ x + y = 97
∴ x + 12 = 97
∴ x = 97 – 12
∴ x = 85
∴ The two numbers are 85 and 12.
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If yes plzz mark it as brainliest answer!!
As per the first given condition,
x + y = 97 ........eq. no. (1)
As per the second condition,
Dividend = Divisor × Quotient + Remainder
x = y × 7 + 1
∴ x = 7y + 1
∴ x – 7y = 1 .......(2)
Subtracting (2) from (1),
x + y = 97
x – 7y = 1
(-) (+) (-)
8y = 98
∴ y = 96/8
∴ y = 12
Substituting y = 12 in equation (1)
∴ x + y = 97
∴ x + 12 = 97
∴ x = 97 – 12
∴ x = 85
∴ The two numbers are 85 and 12.
I hope it helps u!!
If yes plzz mark it as brainliest answer!!
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