The sum of two no. Is 8 and the sum of the reciprocals is 8/5
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Step-by-step explanation:
Hello there,
Refer the pic attached for the step-by-step explanation for your problem.
x = 4 + √11
y = 4 - √11
Hope you find my answer useful.
Harith
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STEP BY STEP EXPLANATION
Let one number be x and the another no. be x
Given,
x+y =8
x=8-y....(1)
By simplifying 1/x +1/y =8/15
We get, (x+y) /xy =8/15
From (1) we get,
8/8 y - y =8/15
Y² - 8y+15=0
(y-3) (y-5)=0
y=3 or 5
We know that x-y=8
When y=5,x-3
When y=3,x=5
Thus,the two no. are 3 and 5
Let one number be x and the another no. be x
Given,
x+y =8
x=8-y....(1)
By simplifying 1/x +1/y =8/15
We get, (x+y) /xy =8/15
From (1) we get,
8/8 y - y =8/15
Y² - 8y+15=0
(y-3) (y-5)=0
y=3 or 5
We know that x-y=8
When y=5,x-3
When y=3,x=5
Thus,the two no. are 3 and 5
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