The sum of two no. is 80if the larger no. exceeds four times the smaller no. by 5,the smaller no. is
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Let the larger number be L
& the smaller number be S
According to the question :
L + S = 80
L = 80 - S ......(i)eq
& also given
L - 4S = 5
L = 5 + 4S...........(ii)eq
from eq (i) & (ii)
5 + 4S = 80 - S
4S + S = 80 - 5
5S = 75
S = 75 /5
S = 15
so the smaller number is 15
and the larger number is 65
hope it will help
& the smaller number be S
According to the question :
L + S = 80
L = 80 - S ......(i)eq
& also given
L - 4S = 5
L = 5 + 4S...........(ii)eq
from eq (i) & (ii)
5 + 4S = 80 - S
4S + S = 80 - 5
5S = 75
S = 75 /5
S = 15
so the smaller number is 15
and the larger number is 65
hope it will help
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