The sum of two no is 84 if one third of the one exeed one seventh of the other by 8 find the smaller number
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21 & 63 these are two numbers
smallest one is 21
hopes it will help you
smallest one is 21
hopes it will help you
Answered by
0
Answer :
Let us consider the two numbers as x and (84 - x), since their sum is 84.
By the given condition, one third of x exceed one seventh of (84 - x) by 8
=> 1/3 x = 1/7 (84 - x) + 8
=> x/3 = 12 - x/7 + 8
=> x/3 + x/7 = 20
=> (7x + 3x)/21 = 20
=> 10x = 210
=> x = 21
Therefore, the smaller number is 21 and the larger number is (84 - 21) = 63
#MarkAsBrainliest
Let us consider the two numbers as x and (84 - x), since their sum is 84.
By the given condition, one third of x exceed one seventh of (84 - x) by 8
=> 1/3 x = 1/7 (84 - x) + 8
=> x/3 = 12 - x/7 + 8
=> x/3 + x/7 = 20
=> (7x + 3x)/21 = 20
=> 10x = 210
=> x = 21
Therefore, the smaller number is 21 and the larger number is (84 - 21) = 63
#MarkAsBrainliest
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