Question

The sum of two no. Is pq and their differenceis 1/7 of their sum find their HCF

Answer 1

Answer:

Let the two numbers be x and y.

x+y=7 ----- (1)

x−y=1 ----- (2)

Adding equation (1) and (2), we get

x+y=7

x−y=1

_________

2x=8

x=8/2=4

Substituting the value x in equation (1), we get

4+y=7

y=7−4

y=3

Therefore, x=4 and y=3

Hence, the two numbers are 4 and 3.

Answer 2

Step-by-step explanation:

$let \: the \: two \: no. \: be \: x \: and \: y \\ \color{blue}{ \underline{according \:to \: the \: question } : } \\ x + y = pq - (i) \\ \\ x - y = \frac{1}{7} pq - (ii) \\ \color{blue}{ \underline{adding \: {eq}^{n} \: (i) \: and \: (ii) } : } \\ \boxed{x = \frac{8pq}{7} } \\ similarly : \boxed{y = \frac{6pq}{7} } \\ x = 2 \times 2 \times 2 \times pq \times \frac{1}{7} \\ y = 2 \times 3\times pq \times \frac{1}{7} \\ hcf = 2 \times pq \times \frac{1}{7} \\ \color{red}\boxed{hcf = \frac{2pq}{7} } \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$