Question

The sum of two non-zero numbers in 12. The minimum sum of their reciprocals is......,Select correct option from the given options.
(a) 1/10
(b) 1/4
(c) 1/2
(d) 1/3

Answer 1

Given that x + y = 12

x and y can be 1&11 , 2&10 , 3&9 , 4&8 , 5&7 and 6&6

Sum of its reciprocal

1/x + 1/y = ( x + y ) / xy

so sum of its reciprocal can be

( 1 + 11 ) / 11 = 12/11

( 2 + 10 ) /20 = 3/5

( 3 + 9 ) / 27 = 4/9

( 4 + 8 ) / 32 = 3/8

( 5 + 7 ) / 35 = 12/35

( 6 + 6 ) / 36 = 1/3

So according given options 1/3 is only possible

your answer is 1/3

Answer 2

Step-by-step explanation:

option d is correct answer