the sum of two nos is 64 and second nos is 16 less then the
first find the number
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Answer:
Let the numbers be x and y
According to frist condition,
x + y = 64 ......(1)
According to second condition,
x - 16 = y ........(2)
Step (1)
From equation (1) x + y = 64
Step (2)
Substitute x + y = 64 in (2)
x - x - 16 = 64
x = 64 + 16
x = 80
Step (3)
Substitute x = 80 in (1)
x + y = 64
80 + y = 64
y = 64 - 80
y = - 16
Verification :-
Substitute x value and y value that we find.
80 - 16 = 64
64 = 64
Here R.H.S = L.H.S
Hence, x = 80 and y = - 16 is the answer.
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