Math, asked by nyonikaajbani, 7 months ago

The sum of two nos is 99 if one of them exceeds the other by 9 find the nos.




please give the answer fully in deatail​

Answers

Answered by vareshnadkarni1997
0

Answer:

45,54

Step-by-step explanation:

let x be an number such that,

x+ (x+9)=99 since one number exceeds other by 9,

2X+9=99,

2x=90

x=45

and another number is 54.

Answered by Anonymous
2

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{\tt{Given :-}}}

 \:\:

  • Sum of two numbers is 99

 \:\:

  • One is greater then the other by 9

 \:\:

 \red{\underline \bold{\tt{To \: Find :-}}}

 \:\:

  • Both the numbers

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

  • Let one number be "x"

  • Let the other number be "y"

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

One is greater then the other by 9

 \:\:

 \bf \dag \ \ \ x = y + 9  -----(1)

 \:\:

Sum of both the numbers is 99

 \bf \dag \ \ \ x + y = 99 ------(2)

 \:\:

 \underline{\bold{\texttt{Putting the value of "x" from (1) to (2) }}}

 \:\:

 \sf \longmapsto y + 9 + y = 99

 \:\:

 \sf \longmapsto 2y + 9 = 99

 \:\:

 \sf \longmapsto 2y = 90

 \:\:

 \sf \longmapsto y = \dfrac { 90 } { 2 }

 \:\:

 \bf \dashrightarrow y = 45 ------(3)

 \:\:

 \underline{\bold{\texttt{Putting y = 45 in (1) }}}

 \:\:

 \sf \longmapsto x = 9 + 45

 \:\:

 \bf \dashrightarrow x = 54

 \:\:

  • Hence the first number is 54 and the other is 45
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