Question

The sum of two nubers is 32 there diffrence is 8

Answer 1

Answer:

Call x and y the 2 numbers.

x + y = 32

x - y = 8

2x = 40  -> x = 20, and y = 32 - 20 = 12.

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Questions}}}}$

Given,

$\textbf{\underline{Sum\;of\;two\;number\;is\;32}}$

$\textbf{\underline{Difference\;is\;8}}$

Assume

Number be x and y respectively

So,

x + y = 32 ....... (1)

x - y = 8 ........... (2)

$\Large{\boxed{\bigstar{{Adding\;both\;Equation :-}}}}$

x + y + (x - y) = 32 + 8

x + y + x - y = 32 + 8

2x = 32 + 8

2x = 40

$\rm \: \: \: \: \: \: \: \: \:x=\dfrac{\cancel{40}}{\cancel{2}}$

x = 20

Hence,

$\Large{\boxed{\bigstar{{First\;number= 20}}}}$

$\Large{\boxed{\bigstar{{Second\;number:-}}}}$

x + y = 32

20 + y = 32

y = 32 - 20

y = 12

Therefore,

$\huge{\boxed{\sf\:{First\;number = 20\;and\;Second\;number = 12}}}$