Question

The sum of two number and number obtained by interchanging digits is always divisible by

Answer 1

9. ,, and 11 ... will be the answer

Answer 2

Let two digit no be 10a + b.

So it's reversal is 10b + a.

According to ur question,

10a + b + 10b + a

= 11a + 11b

= 11(a+b)

Hence it always divisible by 11.

Suppose a number 45.. It's reversal is 54..

Sum = 45+54

= 99

See it clearly divisible by 11..

Hope it's helpful to u.