Question

The sum of two number is 100 . If the fifth part of one is two more than the fourth part of the other, then find both the number.

Answer 1

Answer:

Let the numbers be x and y .

According to the question,

x = 100 - y

x/5 = 2 + y/4

x/5 = (8 + y)/4

4x = 40 + 5y

putting the value of x

4(100-y) = 40 + 5y

400 - 4y = 40 + 5y

400 - 40 = 5y + 4y

360 = 9y

y = 40

x = 100 - 40 = 60

so the number is 60 and 40 ans...

Step-by-step explanation:

hope it helps....

Answer 2

Answer:

The numbers are 40 and 60

Step-by-step explanation:

let the numbers be X and Y

Given : X + Y = 100

            (1/5) × X = 2 + (1/4) × Y         (you can take it the other way round too)

To find : X and Y

Solution :

X + Y = 100    ---> (1)

    (1/5) × X = 2 + (1/4) × Y

==> (X/5) - (Y/4) = 2

==>(4X - 5Y)/20 = 2

==>(4X-5Y) = 40  --->(2)

Solving (1) and (2) -->  Multiply (1) by 4 and subtract (2) from it

==> 9Y = 360

==> Y = 40

     from (1)

     X = 60