Question

the sum of two number is 16 and the sum of their reciprocal is 1 by 3 find the number​

Answer 1

Step-by-step explanation:

x+y=16

1/x+1/y=1/3

or ,(x+y)/xy=1/3

16/xy=1/3

xy =48

now , (16-y)y=48

16y-y^2=48

y^2-16y+48=0

y^2-12y-4y+48=0

y (y-12)-4 (y-12)=0

(y-12)(y-4)=0

so , y=4 or y=12

and x=12 or x=4

Answer 2

Step-by-step explanation:

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