The sum of two number is 16 and the sum of their reciprocals is 1/3. find the numbers
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let the two nos be x and y
x+y=16
x=16-y -(1)
1/x+1/y=1/3
1/16-y
x+y=16
x=16-y -(1)
1/x+1/y=1/3
1/16-y
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