The sum of two number is 18 and their product is 72. The smaller number is?
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Let x and y be the numbers
x + y = 18
y = 18 - x
xy = 72
x(18 - x) = 72
18x - x^2 = 72
x^2 - 18x + 72 = 0
x^2 - 6x - 12x + 72 = 0
x( x - 6) -12( x - 6 ) = 0
(x - 12) ( x - 6 ) = 0
x - 12 = 0
x = 12
x - 6 = 0
x = 6
x + y = 18
Thus the two numbers are 6 and 12
The smallest among this is 6
x + y = 18
y = 18 - x
xy = 72
x(18 - x) = 72
18x - x^2 = 72
x^2 - 18x + 72 = 0
x^2 - 6x - 12x + 72 = 0
x( x - 6) -12( x - 6 ) = 0
(x - 12) ( x - 6 ) = 0
x - 12 = 0
x = 12
x - 6 = 0
x = 6
x + y = 18
Thus the two numbers are 6 and 12
The smallest among this is 6
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