the sum of two number is 184 .if one third of the one exceeds one seventh of the other by 8 ,find the smaller number with full soluction
Answers
Answered by
4
Let the nos are x,y
so x+y=184.... (1)
again x/3-y/7=8
take lcm
7x-3y/21 =8
7x-3y=168...(2)
nowconverting (1)
x+y=184
y=184-x subsitute it in (2)
7x -3(184-x)=168
7x-552+3x=168
10x=720...x=72 now subsitute this in(1)
72+y=184
y=112
x= 72 y=112
so smaller no 72
so x+y=184.... (1)
again x/3-y/7=8
take lcm
7x-3y/21 =8
7x-3y=168...(2)
nowconverting (1)
x+y=184
y=184-x subsitute it in (2)
7x -3(184-x)=168
7x-552+3x=168
10x=720...x=72 now subsitute this in(1)
72+y=184
y=112
x= 72 y=112
so smaller no 72
Similar questions