The sum of two number is 2000. If 25% of the smaller number is one-sixth of the larger, find the numbers
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Answer:
The numbers are 800 and 1200.
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Step-by-step explanation:
Let the two number be 'a' and 'b'.
given,
a+b=2000 _eq1_
also,
25% of the smaller number is 1/6th of the larger number
so, 25/100*a=1/6*b
1/4*a=1/6*b
6a=4b
a=2b/3
substituting the value of "a" in eq1
a+b=2000
2b/3+b=2000
(2b+3b)/3=2000
5b=2000*3
5b=6000
b=1200 sol1
a=2b/3
a=2*1200/3
a=2400/3
a=800 sol 2
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