The sum of two number is 24 and the sum of their square is 386 then one number is??
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Answer:
Step-by-step explanation:
let one number = x
let other number = y
according to question x + y = 24
so, x = 24-y
and,
x^2. +y^2= 386
sub first equation
(24-y)^2 + y^2 = 386
576 + y^2 - 1152y +y^2= 382. ( x - y )^2 = x^2 +y^2-2xy
2y^2 -1152y +576-382
2y^2 - 1152y +194 (divide all terms by 2 )
y^2 - 576y +82
solve the eq and get the answer for y and resub in (x + y =24) for x
hope you like it
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