Question

the sum of two number is 26 and 3 times of 1 them exceeds 5 times the other by 6 find the numbers

Answer 1

Let nos be x and y
x + y = 26 (1)
3x = 5y + 6 (2)
Multiply (1) by 3 and subtract (2) from it

3x + 3y = 78
- 3x - 5y = 6
8y = 72
y = 9
x + y = 26
x = 26 -9 =.17

Answer 2

Let the two numbers be x and y. 
x + y = 26-----------------( 1 )
3x - 5y = 6-----------------( 2 )
From ( 1 ),
y = 26 - x
Substituting ( 1 ) in ( 2 ),
3x - 5( 26 - x ) = 6
=> 3x - 130 + 5x = 6
=> 8x = 6 + 130
=> x = 17

y = 26 - 17
=> y = 9

Therefore, the 2 numbers are 9 and 17.

Hope this helps.

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