Question

the sum of two number is 2604 and their HCF is 124. which is the smaller between them if their difference is least possible​

Answer 1

Answer:

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Answer 2

Answer:

1240

Step-by-step explanation:

x + y = 2604

HCF is 124

For difference to be minimum y=x+124 (Assuming y to be larger number)

Then we get

x+x+124=2604

2x=2604-124

2x=2480

x=1240 (minimum number is x)

Hope this helps you