Question

The sum of two number is 36 and their hcf is 4 find the possible number of pairs

Answer 1

since , we have given H.C.F = 4 of the required numbers then 4 will also be a multiple of those numbers.
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let the numbers be 4a and 4b .

where a, b are integers.

given sum = 36

4a + 4 b = 36

this equation satisfies at a =1 , b = 8

therefore ,

the possible numbers are

4a= 4 × 1 = 4

4b = 4 × 8 = 32
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Reason : here you can see that H.C.F of 4 and 32 is 4 and sum = 36
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therefore , ( 4 , 32 ) will be possible pair of required numbers .

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Your Answer : ( 4 , 32 )
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