the sum of two number is 40.if one no is 5 more than3/2 the other. Find the number
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let first no. be x And second no be y ATQ: x+y=40.......(1) Secondly, (x+5)= 3/2y 2x+10=3y 2x-3y=-10......(2) Multiply (1) by 2 2x+2y=80 2x-3y=-10 (-) (+) (+) 5y=90 y=90/5 y=18......(3) putting (3) into (1) x+18=40 x=40-18 x=22 So, both the nos. are 22 and 18
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