Question

The sum of two number is 40. one number 10 more than other number 0.Find the numbers​

Answer 1

Given: The sum of two numbers is 40. & one of the number is 10 more than the other number.

Need to find: The numbers?

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Let's say, that the numbers are x and y respectively.

• F I r s t⠀C o n d i t i o n :

• One number is 10 more than the other number. Therefore:

$:\implies\sf\quad x = 10 + y \qquad\qquad\qquad\qquad\sf\Bigg\lgroup eq^n\;(i)\Bigg\rgroup$

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• S e c o n d⠀C o n d i t i o n :

• It is given that, Sum of these two numbers is 40. Therefore:

$:\implies\sf\quad First_{\:(number)} + Second_{\:(number)} = 40$

$:\implies\sf\quad x + y = 40$

$:\implies\sf\quad 10 + y + y = 40\qquad\qquad\qquad\qquad\sf\Bigg\lgroup By\;using\;eq^n\;(i)\Bigg\rgroup$

$:\implies\sf\quad 10 + 2y = 40$

$:\implies\sf\quad 2y = 40 - 10$

$:\implies\sf\quad 2y = 30$

$:\implies\sf\quad y = \cancel\dfrac{30}{~2}$

$:\implies\quad\underline{\boxed{\pmb{\frak{y = 15}}}}$

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⠀⠀$\underline{\bf{\dag} \:\:\sf{Now\; Finding\;'x'\; Therefore\: :}}$⠀⠀⠀

$:\implies\sf\quad x + y = 40$⠀

$:\implies\sf\quad x + 15 = 40$

$:\implies\sf\quad x = 40 - 15$

$:\implies\quad\underline{\boxed{\pmb{\frak{x = 25}}}}$

$\therefore{\underline{\textsf{Hence, the two numbers are \textbf{25} and \textbf{15} respectively.}}}$

Answer 2

Let,

• First no. = n

• Second no. = n +10

A.TQ,

⟹ n + 10 + n = 40

⟹ 2n + 10 = 40

⟹ 2n = 40 - 10

⟹ 2n = 30

⟹ n = 30/2

⟹ n = 15

Therefore,

• First no. = n = 15

• Second no. = n + 10 = 15 + 10 = 25