Question

The sum of two number is 4312 .if one of the number is three times the other, What is the greatest number?

Answer 1

Answer:

let x be the greatest no.

and y be the smallest no.

by first condition

x+y=4312------------eqn(1)

by second condition

x=3y

x-3y=0------------------eqn(2)

multiply eqn (1)by 3,we get

3x+3y=12936---------------eqn(3)

add eqn (1)and (3)

3x+3y=12936

x- 3y=0

4x =12936

x=12936divided by 4

x=3234

therefore greatest no. is 3234

if need to smallest no. then

put value of x in eqn(2)

x-3y=0

3234-3y=0

-3y=-3234

minus gets canceled on both sides

3y=3234

y=3234divided by 3

y=1078

therefore smallest no. is 1078