The sum of two number is 50 and their difference is 22 find the number with their solution
Answers
Answered by
34
Hey there!
Given that ,The sum of two numbers is 50 , The difference in two numbers is 22 ,
Let the two numbers be x , y.
Sum of two numbers = x + y = 50 .
Difference of two numbers = x - y = 22 .
So, We are solving the pair of linear equations in two variables.
x + y = 50
x - y =22
=========
2x = 72
x = 72/2 = 36 .
Therefore, x + y = 50
36 + y = 50
y = 50 - 36
y = 14 .
The number are 36 , 14 .
The two numbers are 36 , 14
Given that ,The sum of two numbers is 50 , The difference in two numbers is 22 ,
Let the two numbers be x , y.
Sum of two numbers = x + y = 50 .
Difference of two numbers = x - y = 22 .
So, We are solving the pair of linear equations in two variables.
x + y = 50
x - y =22
=========
2x = 72
x = 72/2 = 36 .
Therefore, x + y = 50
36 + y = 50
y = 50 - 36
y = 14 .
The number are 36 , 14 .
The two numbers are 36 , 14
Answered by
8
Given that ,
The sum of two numbers = 50
And their differences = 22
Find the numbers = ?
Let the two numbers be " a " and " b "
So , According to the question ,
Sum of the two numbers = a + b = 50
And their differences = a - b = 22
On solving ,
=> [ a + b = 50 ] - [ a - b = 22 ]
=> 2a = 72
=> a = 36
♧ Put the value of " a " = 36 ,
=> a - b = 22
=> 36 - b = 22
=> ( - b ) = 22 ( - 36 )
=> ( - b ) = ( - 14 )
=> b = 14
The sum of two numbers = 50
And their differences = 22
Find the numbers = ?
Let the two numbers be " a " and " b "
So , According to the question ,
Sum of the two numbers = a + b = 50
And their differences = a - b = 22
On solving ,
=> [ a + b = 50 ] - [ a - b = 22 ]
=> 2a = 72
=> a = 36
♧ Put the value of " a " = 36 ,
=> a - b = 22
=> 36 - b = 22
=> ( - b ) = 22 ( - 36 )
=> ( - b ) = ( - 14 )
=> b = 14
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