Question

the sum of two number is 56 one number is 8 more than twice the other number find the equation

Answer 1

56=(8+2x)+x
56=8+2x+x
56-8=3x
3x=48
x=48/3
x=16

Answer 2

sum of 2 number = 56

Let one number be x
other number = 2x + 8

the equation is

2x + 8 + x = 56


further ,
it can be solved as,

3x + 8 = 56
3x = 56 - 8
3x = 48

$x = \frac{48}{3}$
x = 16


therefore,

1st number = x = 16
2nd number = 2× 16 + 8 = 40