the sum of two number is 5and difference of their square is 5 find the difference of number
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Let the numbers be x and y
Given :- x+y= 5
x^2-y^2 = 5
Find :- x-y
Therefore,
x^2-y^2 = (x+y)(x-y)
5 = (5)(x-y)
5/5= x-y
x-y = 1
Given :- x+y= 5
x^2-y^2 = 5
Find :- x-y
Therefore,
x^2-y^2 = (x+y)(x-y)
5 = (5)(x-y)
5/5= x-y
x-y = 1
anmita18:
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