Question

the sum of two number is 64 and second number is 16 less than the first find the number​

Answer 1

Answer:

Let the nos.be x and y

x + y = 64

X-y= 16

2x = 80,x=40. Ans

x + y = 64

40+y=64

y = 24. Ans

Answer 2

Answer: 24

Step-by-step explanation:

Let the first number be x.

Let the second number be y.

It is given that their sum is 64.

=> x + y = 64

Taking x to the other side,

y = 64 - x ..... 1

It is also given that the first number is 16 less than the first, i.e. if we add 16 to the first number it will be equal to the second number.

=> x + 16 = y

Plugging in the value of y from 1, we get,

x + 16 = 64 - x

=> x + x = 64 - 16

=> 2x = 48

=> x = 24

So, the first number is 24.

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