the sum of two number is 64 and the second number is 16 less than the first find the numbers one number is 7 times another if 18 is added to the sum of the numbers the result is 38 find the numbers
Answers
Answer:
Step-by-step explanation:
Let one number be x and other y
x+y=64
y=x-16
putting value of y in eq. 1
x+x-16=64
2x=80
x=40
y=40-16=24
Answer:
Question 1: 40 and 24
Question 2: 2.5 and 17.5
Step-by-step explanation:
QUESTION 1
- Write an equation for the question (pro gamer tip: this always helps in questions such as this were you have to find a number)
x + y = 64
y = x - 16
- Substitute x - 16 for y now and rewrite the equation
x + x - 16 = 64
- Simply the equation by collecting like terms
2x - 16 = 64
- Try to get what you are trying to solve alone, in this case:
2x - 16 = 64
+ 16
2x = 80
- Just solve!
2x = 80.
x = 80/2
x = 40
y = 24
QUESTION 2
- Rewrite the question in to an equation
x + y + 18 = 38
x = 7y
- Substitute7y for x ad rewrite the equation
7y + y + 18 = 38
- Simply the equation by collecting like terms
8y + 18 = 38
= Try to get what you are solving alone, in this case:
8y + 18 = 38
- 18 =
8y = 20
- Solve
8y = 20
y = 20/8
y = 2.5
x = 17.5
- Check to see if your answer meets all requirements
2.5 + 17.5 + 18 = 38