Math, asked by rituy91773, 6 months ago

the sum of two number is 64 and the second number is 16 less than the first find the numbers one number is 7 times another if 18 is added to the sum of the numbers the result is 38 find the numbers​

Answers

Answered by aithimouleendra
0

Answer:

Step-by-step explanation:

Let one number be x and other y

x+y=64

y=x-16

putting value of y in eq. 1

x+x-16=64

2x=80

x=40

y=40-16=24

Answered by appukoreth
0

Answer:

Question 1: 40 and 24

Question 2: 2.5 and 17.5

Step-by-step explanation:

QUESTION 1

- Write an equation for the question (pro gamer tip: this always helps in questions such as this were you have to find a number)

x + y = 64

y = x - 16

- Substitute x - 16 for y now and rewrite the equation

x + x - 16 = 64

- Simply the equation by collecting like terms

2x - 16 = 64

- Try to get what you are trying to solve alone, in this case:

2x - 16 = 64

    + 16

2x = 80

- Just solve!

2x = 80.

x = 80/2

x = 40

y = 24

QUESTION 2

- Rewrite the question in to an equation

x + y + 18 = 38

x = 7y

- Substitute7y for x ad rewrite the equation

7y + y + 18 = 38

- Simply the equation by collecting like terms

8y + 18 = 38

= Try to get what you are solving alone, in this case:

8y + 18 = 38

    - 18 =

8y         = 20

- Solve

8y = 20

y = 20/8

y = 2.5

x = 17.5

- Check to see if your answer meets all requirements

2.5 + 17.5 + 18 = 38

Similar questions