Question

The sum of two number is 72 and the difference is 40. Find the numbers.​

Answer 1

Answer:

56 and 16

Step-by-step explanation:

Set up equations!

x+y=72

x-y=40

You can solve for this by crossing out y as it becomes eliminated. You are left with 2x= 112. Then solve, so x= 56. Take 56 for x and plug it into one of the equations and solve for y. 56-y=40-----> y= 16. The numbers are 16 and 56.

Answer 2

Answer:

Two numbers are  56  and 16

Step-by-step explanation:

According to the information provided in the question it is given as

The sum of two number is 72

And the difference is 40.

We need to find the the numbers.​

Let make an equation by assuming numbers as x, y

x + y =72 -------- (1 )

x - y = 40---------( 2)

Now adding  (1),(2)

2x = 112

x=112 /2

x= 56

Now substituting the value of x in equation (1)

x + y = 72

56 + y = 72

y = 72 -56

y = 16

Hence x = 56 and y = 16

So the two numbers are 56 and 16