Question

the sum of two number is 74 if one of the number is ten more than the other than what are the numbers pls say the step wise and full method

Answer 1

Heya.....

Let the no. Be x
Second no. Would be 10+x

X+10+x=74
2x=74-10=64
X=32

@skb

Answer 2

Here is your solution,

Let the first no. be x

Let the second no. be y

Now, ATQ

x+y = 74 -1

x = y+10 -2

Apply any method u like to solve these equations. I am using substitution method,

From 1,

x = 74-y -3

put 3 in 2

74-y = y+10

-y-y = 10-74

-2y = -64

y = -64/-2

y = 32 -4

Now, put 4 in 1

x+32 = 74

x = 74-32

x = 42

So, 1st no. (x) is = 42

and

2nd no. (y) is = 32

Hope it helped...........