the sum of two number is 8 and their difference is 4 .find the numbers.
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Hence, the numbers are "6 and 2".
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Let the number be (x).
x + y = 8 ------- ( 1 )
x - y = 4 ---------( 2 ) [ x > y ]
x = 8 - y
Put x = 8 - y in ( 2 )
8 - y - y = 4
=> 8 - 2y = 4
=> - 2y= 4 - 8
=> - 2y= - 4
y = 2
Replace the value of y = 2 in the equation,
x = 8 - y
=> x = 8 - 2
=> x = 6
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