Question

the sum of two number is 80 and if the larger number exceed 14 x smaller by the five what is the smaller number​

Answer 1

Correct Question

The sum of two number is 80 and if the larger number exceed 4 times the smaller by 5.

Find out

• The smaller number

Solution

★ Let the larger number be x and smaller number be y

According the given condition

✒Sum of two numbers is 80

• x + y = 80 ----(i)

✒If the larger number exceed 14 times the smaller by 5

• x = 4y + 5
• x - 4y = 5 -----(ii)

✑ Subtract both the equations

➟ (x + y) - (x - 4y) = 80 - 5

➟ x + y - x + 4y = 75

➟ 5y = 75

➟ y = 75/5 = 15

✑ Putting the value of x in eqⁿ (i)

➟ x + y = 80

➟ x + 15 = 80

➟ x = 80 - 15 = 65

Hence,

• Larger number = x = 65
• Smaller number = y = 15

$\rule{200}3$

Answer 2

Answer:

Given:

→ The sum of two number is 80 and if the larger number exceed 14x smaller by the five.

Find:

→ What is the smaller number.

Calculations:

→ Let us assume x as larger number and y as lesser number.

___________________________________

→ $\sf{x = 14x}$

→ $\sf{y = 5y}$

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→ $\sf{x + y = 80}$

→ $\sf{80 - 5 = 75}$

→ $\sf{5y = 75}$

→ $\sf{y = \dfrac{75}{5}}$

→ ${\sf{\underline{\boxed{\red{\sf{y = 15}}}}}}$

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→ $\sf{x = 80 - 15y}$

→ ${\sf{\underline{\boxed{\red{\sf{x = 65}}}}}}$

Therefore, the smaller number is 15 and the larger number is 80.