Math, asked by utkarshsUtkarsh4112, 1 year ago

The sum of two number is 80 and the greater number.ex exceed twice the smaller number
by 11 . Find the number.

Answers

Answered by sreerajsahu
0
the nos are 23 and 57 respectively.

sreerajsahu: plz mark this as brainliast
sreerajsahu: thanks
Answered by NehaNagal
0

 \huge\underline\mathcal\pink{Answer}

Let the number be x

Then greater number = 2x + 11

Sum of two numbers = 80

x + 2 + 11 = 80

3x = 80 - 11

3x = 69

x = 23

Hence, smaller number = 23

Greater number = 2 × 23 + 11 = 57

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