Question

the sum of two number is 80 and the greater number exceeds twice the number by 11 find the number​

Answer 1

Step-by-step explanation:

The n and m be your numbers. The sum of the numbers is 80, so m + n = 80.

Let m is the greater number. It exceeds twice the smaller number, n, by 11. m = 2n + 11

So, we have two equations and two unknowns:

m + n = 80

m = 2n + 11

or, we can rewrite the second equation

m + n = 80

m -2n = 11

Multiply through the top equation by 2.

2m + 2n = 160

m -2n = 11

Now add the two equations, which will eliminate n.

3m = 171

or

m = 57

We can now use one of the original equations and solve for n knowing this value of m. Let's use the first equation m + n = 80.

n = 80 - m

or

n = 80 - 57 = 23

So, m = 57 and n = 23

Answer 2

Step-by-step explanation:

Let the smaller number be x

Then the bigger will be 11 + 2x

A/q,

=> 11 + 2x + x = 80

=> 3x = 80-11

=> x = 69

=> x = 23 ans.

And, also 11 + 2x = 11 + 46 = 57 ans.