Question

the sum of two number is 80 and the greater number exceeds twice the smaller by 11 find the numbers?
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Answer 1

Answer:

69/2 and 91/2

Step-by-step explanation:

let 1 number is x

and 2 number is x+11

x+x+11=80

2x =80-11

2x=69

x=69/2

and x=91/2

Answer 2

$\huge\sf\underline{\underline{Answer:}}$

• Greater no. = x = 57
• Smaller no. = 23

_______________________________________

The sum of two numbers is 80.

Thus,

Let the greater number be "x" then smaller number will be "(80-x)"

Also,

The greater number exceeds twice the smaller by 11.

Thus,

Greater no. = 2•(Smaller no.) + 11

⇒x = 2(80-x) + 11

⇒ x = 160 - 2x + 11

⇒x + 2x = 160 + 11

⇒3x = 171

⇒x = 171/3

⇒x = 57

Hence,

Greater no. = x = 57

Smaller no. = 80-x = 80-57 = 23

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